Scripts / [SOLVED] table library

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Flatlander
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Posted: 7th Mar 2020 18:47
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In version 5.1 of Lua, they added "table.maxn". GG uses Lua 5.2 and I assumed it should also be available; but, that seems not to be the case. When I use this: max_elements = table.maxn(g_weapons) the error message tells me that "trying to call the field 'maxn' a nil value". So, is this deprecated in 5.2? Or, it just is allowed to work in GG?
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AmenMoses
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Posted: 7th Mar 2020 19:14 Edited at: 7th Mar 2020 19:17
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Looks like it got taken out of 5.2 as it's not in the 5.2 manual (which is free online btw).

https://www.lua.org/manual/5.2/manual.html#6.5
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Flatlander
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Posted: 7th Mar 2020 21:50
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Thanks, AM. I guess I was looking in the 5.1 manual. I played around with a couple of ways to get the max number and decided on the following code. Of course, if it is a really long list it may take too long to iterate through the list.

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AmenMoses
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Posted: 7th Mar 2020 22:26
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That wouldn't give the same result!

If g_weapons is a simple contiguous list (i.e. like an array) then #g_weapons will tell you how many entries it has.

If otoh it is a more complex list then:


Will tell you how many entries there are in the list.

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Flatlander
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Posted: 8th Mar 2020 03:36
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I'm using the list as an array. I was looking at two or three Lua forums and there was a discussion about whether or not to use table.maxn or to use the '#' sign. I couldn't believe it would be that simple just to use the '#' in front of the list name. But, by golly, it do work. Thanks for the suggestion.
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AmenMoses
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Posted: 8th Mar 2020 12:13
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Yes as long as you have list[1], list[2], …. list[n] as keys than #list will work.

In fact to ensure that this is the case when adding to an array simply use:

list[ #list + 1 ] = value

That way you ensure to grow the 'array' in a contiguous way.

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